[erlang-questions] what does when do here? fib(1200000) so slow, erlang cant handle big numbers?

[Edwin Fine]

It finishes on my system in 46 seconds. It produces a number that is 250785
digits long. That's a humungous, massive, mind-bogglingly large number. A
googol (10^100) only has 100 digits. This is 2500x the size of a googol. I
would *guess* that although the *algorithm* is linear, you are hitting a
non-linearity in the large number representation in Erlang, maybe due to GC
or memory growth. I dunno. I mean, you are adding together two massive
numbers over and over towards the end. The N > 0 prevents infinite recursion
if you call fib(-1).

2008/7/1 Circular Function <circularfunc@REDACTED>:

> what does when N>0 do here? seems like no difference.
> and would you consider this good idiomatic erlang(ofc there is an even
> faster one that i found, posted at the end)?
>
> also, this is linear right? so why does fib(1200000) never finsih? erlang
> cant handle such big numbers? because 12000 is pretty much instant and
> 120000 takes a second or so.
>
> fib_i(A, _B, 0) -> A;
> fib_i(A, B, N) when N > 0 -> fib_i(B, A + B, N - 1).
> fib(N) -> fib_i(0, 1, N).
>
> fib_i(A, _B, 0) -> A;
> fib_i(A, B, N)  -> fib_i(B, A + B, N - 1).
> fib(N) -> fib_i(0, 1, N).
>
>
>
>
>
>
> fibo3(0, _, Pair) -> Pair;
> fibo3(N, {Fib1, Fib2}, Pair) when N rem 2 == 0 ->
>     SquareFib1 = Fib1*Fib1,
>     fibo3(N div 2, {2*Fib1*Fib2 - SquareFib1, SquareFib1 + Fib2*Fib2},
> Pair);
> fibo3(N, {FibA1, FibA2}=Pair, {FibB1, FibB2}) ->
>     fibo3(N-1, Pair, {FibA1*FibB2 + FibB1*(FibA2 - FibA1), FibA1*FibB1 +
> FibA2*FibB2}).
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