[erlang-questions] why each erlang process sets 233 words as its default heap size?
Pierpaolo Bernardi
olopierpa@REDACTED
Thu Sep 20 20:30:07 CEST 2007
On 9/20/07, Jeremy Chow <coderplay@REDACTED> wrote:
> Hi all,
> My first instinction is that it want to club together with one process
> size to reach exactly 1024 bytes . But each process has more than 1024/4
> -233 = 23 words size .
> What's the author's original intention? why each erlang process sets
> 233 words as its default heap size?
The heap size is a fibonacci number.
<guess>
Maybe 233 is the smallest fibonacci number that allows to do something useful.
</guess>
The sequence is: ... 89 144 233 377 610 ...
P.
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