[erlang-questions] parallel tcp server closed once spawned

Bengt Kleberg <>
Tue Oct 16 14:50:18 CEST 2007


if you write para_server_1/0 you are dividing an atom (para_server_1) 
with 0. that is a sure way to crash.
luckily enough you are doing it in a seperate process and the rest of 
your applicaiton will survive :-)


bengt
Those were the days...
    EPO guidelines 1978: "If the contribution to the known art resides
    solely in a computer program then the subject matter is not
    patentable in whatever manner it may be presented in the claims."


On 2007-10-16 14:40, Michael Campbell wrote:
> As a tangent to this conversation...
> 
> On 10/16/07, Chandru <> wrote:
>> I've included a modified version of the
>> para_server which will work whether you spawn or call it directly from
>> the shell.
> 
> 
>> para_server() ->
>>     spawn(fun() ->
>>                   para_server_1()
>>           end).
> 
> 
> Is there a difference in the spawn call above and:
> 
> spawn(fun() ->
>             para_server_1/0
> end).
> 
> ?   I've seen in other examples the M:F/A format for methods that take
> a fun, and wondered if this were a stylistic or subtle "real"
> difference.
> _______________________________________________
> erlang-questions mailing list
> 
> http://www.erlang.org/mailman/listinfo/erlang-questions



More information about the erlang-questions mailing list