[erlang-questions] apply/2

[Bob Ippolito]

I wasn't disagreeing with you, I was clarifying the previous
misinterpretation of how apply/2 should work and using your message as
a correct example of apply/3. Coffee much?

On 7/27/07, David Mercer <dmercer@REDACTED> wrote:
> Bob, I think you misinterpreted.  I wasn't saying that it SHOULD work but
> does not.  I was saying it should work AND DOES.  I was showing the original
> poster how to modify his statement to get the answer he desires.
>
> That being said, as the poster seems adamant about not specifying the module
> name, the following should work AND DOES:
>
> > apply(fun(X) -> round(X) end, [2.3]).
>
> DBM
>
> -----Original Message-----
> From: Bob Ippolito [mailto:bob@REDACTED]
> Sent: Friday, July 27, 2007 12:17
> To: dmercer@REDACTED
> Cc: erlang-questions@REDACTED
> Subject: Re: [erlang-questions] apply/2
>
> apply/2 takes a fun, not the name of the function (an atom)... to use
> apply/2 you'd do this:
>
> apply(fun erlang:round/1, [2.3]).
>
> apply/3 takes the name of the module, the name of the function (both
> atoms), and the arguments as demonstrated.
>
> -bob
>
> On 7/27/07, David Mercer <dmercer@REDACTED> wrote:
> > Fun round is in the erlang module.  This should work:
> >
> > > apply(erlang, round, [2.3]).
> >
> > Cheers,
> >
> > David
> >
> > -----Original Message-----
> > From: erlang-questions-bounces@REDACTED
> > [mailto:erlang-questions-bounces@REDACTED] On Behalf Of Henrique
> Ferreiro
> > Sent: Friday, July 27, 2007 11:42
> > To: erlang-questions@REDACTED
> > Subject: [erlang-questions] apply/2
> >
> > Hello,
> >
> > I noticed some extrange behaviour that this list surely can explain:
> >
> > 1> round(2.3).
> > 2
> > 2> apply(round, [2.3]).
> >
> > =ERROR REPORT==== 27-Jul-2007::18:40:22 ===
> > Error in process <0.31.0> with exit value:
> >
> {{badfun,round},[{erl_eval,do_apply,5},{shell,exprs,6},{shell,eval_loop,3}]}
> >
> > ** exited: {{badfun,round},
> >             [{erl_eval,do_apply,5},{shell,exprs,6},{shell,eval_loop,3}]}
> > **
> >
> > Thanks in advance,
> > Henrique Ferreiro
> >
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