8 bit signed float possible?
Fri Jun 16 17:06:46 CEST 2006
Only 32 and 64 bits are supported.
Ericsson, Björn <> writes:
> I'm trying to construct an eight bit signed float in binary format:
> Float = 3.14.
> Bin = <<Float:8/signed-float>>.
> This only give badarg error. Is 8 bits too small for a float? Manual says default is 64 bits, but I cant find info on minimum.
> Any clues?
> This e-mail and any attachment is for authorised use by the intended recipient(s) only. It may contain proprietary material, confidential information and/or be subject to legal privilege. It should not be copied, disclosed to, retained or used by, any other party. If you are not an intended recipient then please promptly delete this e-mail and any attachment and all copies and inform the sender. Thank you.
Björn Gustavsson, Erlang/OTP, Ericsson AB
More information about the erlang-questions