[erlang-questions] List pipe syntax
Robert Virding
robert.virding@REDACTED
Thu Dec 21 10:45:02 CET 2006
I think there is one thing that you must realise with the [Head|Tail]
construction. It actually builds a pair in which the Head and Tail can
be any term. However, Erlang has extra support, both syntax and
libraries, for a specific usage of pirs, as lists. I.e. where the tail
is a list (pair) or []
So syntax-wise:
[1] is syntactic sugar for [1|[]]
[1,2] -"- [1|[2|[]]]
[1,b,2] -"- [1|[b|[2|[]]]]
[1,2|Tail] -"- [1|[2|Tail]]
etc.
This also shows why you can use the [Head|Tail] to add an element to the
front of a list or match a list and remove the first element (the head).
Also all library functions on lists assume and support this usage, as do
most (all?) applications which use lists.
The is_list/1 test just tests that the top level of its argument is
either a [H|T] or a [], it does not do a deep test.
This means that you can actually use pairs to build data general
structures although this is not recomended as it can easily confuse
people. Use tuples instead. In Lisp however this usage of conses (what
they are called in Lisp) is common.
Robert
Alexander Harju wrote:
> Hi,
> I have a question about the pipe syntax when building lists.
> According to the Erlang reference a list is either the empty list [] or
> consists of a head and a tail which is also a list. [Head|Tail].
> I've noticed that you can do some weird "list"-building using the pipe
> syntax.
> [1|[]] is obviously a list according to the definition since [] is a list.
> But what about [1|2]??. This shouldn't evaluate to a list since 2 isn't a
> list. I checked it with erlang:is_list([1|2]) which returned true. You can
> also use the matching [H|T] = [1|2] where H is bound to 1 and T is bound
> to 2. [1|2] == [1,2] returns false.
> I figured that [1|2] was evaluated to a list of length 1 with the strange
> element 1|2, but erlang:length([1|2]) exits with a badarg.
> It's definitely not a list, but what is it then and why does
> erlang:is_list return true?
> // Alex
>
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