lists:keymerge/3
Jay Nelson
jay@REDACTED
Tue Nov 2 17:43:01 CET 2004
Try the following (it's the best I could think of offhand, but it hasn't
been tested):
listreplace([], Result) -> Result;
listreplace([{Key, Value} = Tuple | More] , List2) ->
Newlist = lists:keyreplace(Key, 1, List2, Tuple),
listreplace(More, Newlist).
You'll want to do lists:keysort(1,List2) before sending it in to
listreplace.
I subscribe to Bjorn's approach of ordering the variable names. The
most important point is the pattern of the tuple, I label it as an
afterthought because I found after I started writing the function that I
needed a handle for the whole term.
It is a matter of style (or conformity, depending on your co-conspirators).
jay
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