R = catch foo() ?
Fri Mar 14 23:00:57 CET 2003
On Fri, 14 Mar 2003, Shawn Pearce wrote:
>Why is this ok:
> case catch foo() of
> R -> ....
>and this is not?
> R = catch foo(),
It has to do with the precedence rules in the parser.
R = (catch foo()),
Ulf Wiger, Senior Specialist,
/ / / Architecture & Design of Carrier-Class Software
/ / / Strategic Product & System Management
/ / / Ericsson AB, Connectivity and Control Nodes
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