Wed Feb 19 18:47:39 CET 2003
You could convert them to integers, bxor them and then convert the result to
a binary again.
bin_bxor(Bin1, Bin2) ->
Sz1 = size(Bin1)*8,
Sz2 = size(Bin2)*8,
<<Int1:Sz1>> = Bin1,
<<Int2:Sz2>> = Bin2,
Int3 = Int1 bxor Int2,
Sz3 = max(Sz1, Sz2),
max(Int1, Int2) when Int1 >= Int2 -> Int1;
max(Int1, Int2) when Int1 < Int2 -> Int2.
From: Dan Melomedman [mailto:dan-erlang@REDACTED]
Sent: 19 February 2003 17:29
Subject: Re: bxor
Matthias Lang wrote:
> Dan Melomedman writes:
> > Hi. I need to bxor other datatypes than integers. What's the
> > recommended way of doing something like this? Thanks.
> It depends on what you want to do and how fast you want to do it and
> how long you want to spend programming it.
It doesn't need to be fast, and I don't want to spend too much time
programming just to be able to XOR. So I am hoping there's an easy way.
> A simple byte-wise approach to XOR-ing the binary Bin with a constant is:
> list_to_binary( [X bxor 123 || X <- binary_to_list(Bin)] )
I think initially I'd like to be able to XOR two binaries. Or two lists.
What if the sizes of the two binaries differ? Will I need to pad one of
them to the size of the other? Thanks much.
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